Math, asked by ronitdwivedi2, 17 days ago

A. Mr Kumar bought the following items from Toys Corner, Kamla Nagar, Delhi on 13 March 2020. Prepare a bill for these items. (a) One teddy bear at 75 per piece. (b) Three toy cars at * 45.50 per car. (c) Two building blocks at * 36 per block. (d) One jig-saw puzzle for 85.50.​

Answers

Answered by aliason20005
1

Answer:

333

Step-by-step explanation:

Total number of teddy bears = 1

Total number of toy cars = 3

Total number of building blocks = 2

Total number of jigsaw puzzle(s) = 1

Cost of 1 teddy bear = 75

Cost of 1 building block = 36

Cost of 1 toy car = 45.50

Cost of 1 jigsaw puzzle = 85.50

Cost of 1 teddy bear = 75x1 = 75

Cost of 3 toy cars = 45.50x3 = 136.50

Cost of 2 building blocks = 36x2= 73

Cost of 1 jigsaw puzzle = 85.50x1= 85.50

Total Cost of items bought = 75+36+136.50+85.50= 333

Please add the units of the amount since you haven't mentioned it.

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