A ms. bar has a diameter of 10 mm and is 350 mm long. A tensile load of 15 kN is applied longitudinally. Calculate the extension of the bar, the change in diameter and change in volume. Assume E = 2 x 10⁵ N/mm' and the Poisson's ratio is 0.25
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Explanation:
bar diameter= 10 mm
2×10⁵/0.25
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