Math, asked by Pragadeesh7042, 10 months ago

A multi-storey building has 16 floors above the ground level each of height 5m. It also has 3 floors in the basement each of height 5m. A lift in building moves at a rate of 1m/s. If a man starts from 45 m above the ground, how long will it take him to reach at 2nd floor of basement?

Answers

Answered by aryman001
2

Answer:

It will take that person 55 seconds to reach the second floor of the basement.

Step-by-Step Explanation:

See,

Speed of the lift:1m/s

Height of each floor:5 metres

Time taken by the lift to cover one floor: speed×distance

That is, 1m/s×5m=5 seconds

Floors between 9th floor above the ground and 2nd floor of the basement=9 floors above the ground and 2 floors below the ground

That is,

9+2=11

So,

Time taken by the lift to cover one floor=5 seconds

Time taken by the lift to cover 11 floors= speed×distance

5 metres×11 floors=55 seconds

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