Math, asked by anoushka200803, 8 months ago

A multi-storey building has 25 floors above the ground level, each of height 5m. It also has 3 floors in
the basement, each of height 5m. A lift in the building moves at a rate of 1 m/sec. If a man starts from
50m above the ground, how long will it take him to reach the 2nd floor of the basement?

Answers

Answered by zain1792
3

Answer:

Each floor has the height of 5m and basement of 3 floors.

If a man starts from 50m above ground and reached at 2

nd

floor of basement.

Distance traveled above basement =50 m

And below basement =2×5=10 m

Total distance traveled=(50+10)m=60m

Rate of moving of a lift =1m/s

that is in 1 second it moves 1 metre.

So, time taken to reach 60 metre =60×1=60 s

Hence, a man reaches at 2

nd

floor of basement in 60 seconds.

Similar questions