A multiple choice examination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability that a student will get 4 or more correct answers just by guessing is :
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The probability will be zero because each question has 3 choices in which only one answer is correct so how can any student get 4 or more answers
Hope my answer will help you buddy
Hope my answer will help you buddy
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Answer:
It should be (c) 11/3^5
Explanation:
We want at least 4 correct answers.
So, we can have two cases:
1) All 5 correct
Probability = (1/3)^5 [Only one choice is correct out of three for 5 questions]
2) 4 correct and 1 wrong.
For 4 correct, Probability = 1/3^4
For 1 wrong: 2/3
Probability = (1/3^4) * (2/3) = 2/3^5
Lekin any one of the 5 questions might have gone wrong. So there are 5 possibilities for the single wrong answer:
So, Probability = (2/3^5) *5 = (10/3^5)
Final, both cases add:
Net Probability: 1/3^5 + 10/3^5 = 11/3^5
Step-by-step explanation:
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