Question

a. Multiply (x-5) by 2x+3
b. subtract 2p(p-q+3r) from 4p(5r-2p+3p)

I want whole process of this please help​

Answer 1

Answer:

1. (x-5)(2x+3)

x(2x+3)-5(2x+3)

2x²+3x-10x-15

2x²-7x-15

2. 4p(5r-2p+3p)-2p(p-q+3r)

20pr-8p²+12p²-2p²+2pq-6pr

-8p²+12p²-2p²+2pq-6pr+20pr

2p²+2pq+14pr

Answer 2

Answer:

Solution :-

$\longmapsto$ Multiply :

$\implies$ $\sf (x - 5)(2x + 3)$

$\implies$ $\sf 2x(x - 5) + 3(x - 5)$

$\implies$ $\sf 2{x}^{2} - 10x + 3x - 15$

$\implies$ $\sf\bold{\red{2{x}^{2} - 7x - 15}}$

$\rule{300}{2}$

$\longmapsto$ Subtract :

$\implies \sf 4p(5r - 2p + 3p) - 2p(p - q + 3r)$

$\implies \sf 20pr - 8{p}^{2} + 12{p}^{2} - (2{p}^{2} - 2pq + 6pr)$

$\implies \sf 20pr - 8{p}^{2} + 12{p}^{2} - 2{p}^{2} + 2pq - 6pr$

$\implies \sf - 8{p}^{2} + 12{p}^{2} - 2{p}^{2} + 20pr - 6pr + 2pq$

$\implies \sf 4{p}^{2} - 2{p}^{2} + 14pr + 2pq$

$\implies \sf\bold{\red{2{p}^{2} + 14pr + 2pq}}$

$\rule{300}{2}$