Math, asked by keerthanas4464, 1 month ago

A multistorey building has 25 floors above ground level, each of height 5m. It also has 3 floors in the basement, each of height 5m. The lift in the building moves at the rate of 5m/sec. If a man starts from 50m above the ground level, how long will it take him to reach at the 3rd floor in the basement?
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Answers

Answered by saminaseer050
1

Answer:

Each floor has the height of 5m and basement of 3 floors.

If a man starts from 50m above ground and reached at 2

nd

floor of basement.

Distance traveled above basement =50 m

And below basement =2×5=10 m

Total distance traveled=(50+10)m=60m

Rate of moving of a lift =1m/s

that is in 1 second it moves 1 metre.

So, time taken to reach 60 metre =60×1=60 s

Hence, a man reaches at 2

nd

floor of basement in 60 seconds.

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