Question

A multistorey building has 25 floors above the 5m. A lift in building moves at a rate 1m/s . if a man starts from 50 m above the ground how long it will it take time to 2nd floor of basement​

Answer 1

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Each floor has the height of 5m and basement of 3 floors.

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement.

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 m

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 m

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 mTotal distance traveled=(50+10)m=60m

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 mTotal distance traveled=(50+10)m=60mRate of moving of a lift =1m/s

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 mTotal distance traveled=(50+10)m=60mRate of moving of a lift =1m/s that is in 1 second it moves 1 metre.

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 mTotal distance traveled=(50+10)m=60mRate of moving of a lift =1m/s that is in 1 second it moves 1 metre.So, time taken to reach 60 metre =60×1=60 s

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 mTotal distance traveled=(50+10)m=60mRate of moving of a lift =1m/s that is in 1 second it moves 1 metre.So, time taken to reach 60 metre =60×1=60 sHence, a man reaches at 2

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 mTotal distance traveled=(50+10)m=60mRate of moving of a lift =1m/s that is in 1 second it moves 1 metre.So, time taken to reach 60 metre =60×1=60 sHence, a man reaches at 2 nd

Each floor has the height of 5m and basement of 3 floors.If a man starts from 50m above ground and reached at 2 nd floor of basement. Distance traveled above basement =50 mAnd below basement =2×5=10 mTotal distance traveled=(50+10)m=60mRate of moving of a lift =1m/s that is in 1 second it moves 1 metre.So, time taken to reach 60 metre =60×1=60 sHence, a man reaches at 2 nd floor of basement in 60 seconds.

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Answer 2

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