Math, asked by neelam112, 1 year ago

a multistorey building has 25 floors above the ground level each off height 5m. it also has 3 floors in the basement each of height 5m. a lift in buliding moves at a rate of 1m/s. if a man starts from 50m above the ground, hwo long will it take him to reach at 2nd floor of basement?

Answers

Answered by ReetChauhan1112
23
total height of building=28×5=140m
the man is at 50m from ground
so, it is from 65m from basement
at 2 floor from basement=5m

so,

total distance=65-5=60m
speed of lift=1m/s
time=distance/speed= 60/1=60s=1min

neelam112: thanxs
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neelam112: simplify which i have written
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ReetChauhan1112: the answer is this only
ReetChauhan1112: check the answer in ur book
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Answered by singvikrambhoomi
4

Answer:

total height of building=28×5=140m

the man is at 50m from ground

so, it is from 65m from basement

at 2 floor from basement=5m

so,

total distance=65-5=60m

speed of lift=1m/s

time=distance/speed= 60/1=m

Step-by-step explanation:

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