Question

A multistorey building has 25 floors above the ground level,each of height 5m.It also has 3 floors in the basement,each of height 5m.A lift in the building moves at the rate of 1m/s.If a man starts from 50m above ground,how long will it take him to reach the 2nd floor of basement???



solve on notebook
(100 marks question)
no wrong answer​

Answer 1

Your Answer:

Given:-

• Total floors = 25 + 3 = 28 floors
• Each floor of height = 5m
• Speed of lift = 1m/s
• A man starts from 50m above the ground.

To find:-

• How long will it take him to reach the 2nd floor of basement

Solution:-

Distance Between Ground floor and 2nd floor of basement is = $\tt 5 \times 2=10m$

So,

The total distance between 2nd floor of basement and 50 m above the ground =50+10=60 m.

So,

$\tt Time =\dfrac{Distance}{Speed} \\\\ \tt \Rightarrow Time=\dfrac{60m}{1m/s} \\\\ \tt \Rightarrow Time=60sec$

So, Time is 60 seconds.