Math, asked by birthday123457, 2 months ago

A multistorey building has 25 floors above the ground level each of height 5m.

It also has 3 floors in the basement each of height 5m. A lift in building moves

at a rate of 1m/s. If a man starts from 50m above the ground, how long will it

take him to reach at 2nd floor of basement?​

Answers

Answered by rashi2623
5

Answer:

Each floor has the height of 5m and basement of 3 floors.

If a man starts from 50m above ground and reached at 2

nd

floor of basement.

Distance traveled above basement =50 m

And below basement =2×5=10 m

Total distance traveled=(50+10)m=60m

Rate of moving of a lift =1m/s

that is in 1 second it moves 1 metre.

So, time taken to reach 60 metre =60×1=60 s

Hence, a man reaches at 2

nd

floor of basement in 60 seconds.

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