A multistorey building has 25 floors above the ground level each of height 5m.
It also has 3 floors in the basement each of height 5m. A lift in building moves
at a rate of 1m/s. If a man starts from 50m above the ground, how long will it
take him to reach at 2nd floor of basement?
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Answer:
Each floor has the height of 5m and basement of 3 floors.
If a man starts from 50m above ground and reached at 2
nd
floor of basement.
Distance traveled above basement =50 m
And below basement =2×5=10 m
Total distance traveled=(50+10)m=60m
Rate of moving of a lift =1m/s
that is in 1 second it moves 1 metre.
So, time taken to reach 60 metre =60×1=60 s
Hence, a man reaches at 2
nd
floor of basement in 60 seconds.
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