A multistorey building has parking floor at the basement. A lift moves at the rate of 4 m per 15 seconds. If the lift starts coming down from a height of 40 m, then find its position after 3 minutes.
Answers
Question :-
A multistorey building has parking floor at the basement. A lift moves at the rate of 4 m per 15 seconds. If the lift starts coming down from a height of 40 m, then find its position after 3 minutes.
Answer :-
A multistory building has parking floor at the basement. A lift moves at the rate of 4m, per 15 seconds.
To find :-
Position of lift after 3 minutes .
Solution :-
★Lift speed = 4 m/sec
★lift initial position = 40 m height
position after 3 minutes,
1 minute = 60 secs
therefore, 3 minutes = 3 × 60 = 180 secs
Lift moves in 15 secs = 4 m
Lift moves in 1 sec = m
Lift will move in 180 secs = 18 ×
Lift will move in 180 secs = 12 × 4 m
Position of lift after 3 minutes = 40 - 48 = (-8)m
lift position will be at depth of 8m.
Lift position will be at the depth of 8m after 3 minutes.
A multistorey building has parking floor at the basement. A lift moves at the rate of 4 m per 15 seconds. If the lift starts coming down from a height of 40 m, then find its position after 3 minutes.
We know that,
1 minute = 60 secs
∴ 3 minutes = (60) (3)
= 180 secs
Distance covered by the lift in 15 sec = 4 m
Distance covered by the lift in 1 sec =
Distance covered by the lift in 180 secs = 18 × m
= (12)(4) m
= 48 m
∴ Position of the lift after 3 minutes (180 secs) = 40 - 48
= -8 m
∴ The lift will be at a depth of 8 m from the ground after 3 minutes.
Hope this helps! ♡