Math, asked by Roastie, 4 months ago

A multistorey building has parking floor at the basement. A lift moves at the rate of 4 m per 15 seconds. If the lift starts coming down from a height of 40 m, then find its position after 3 minutes.​

Answers

Answered by MrAnonymous412
120

Question :-

A multistorey building has parking floor at the basement. A lift moves at the rate of 4 m per 15 seconds. If the lift starts coming down from a height of 40 m, then find its position after 3 minutes.

Answer :-

\longrightarrowA multistory building has parking floor at the basement. A lift moves at the rate of 4m, per 15 seconds.

To find :-

\longrightarrowPosition of lift after 3 minutes .

Solution :-

★Lift speed = 4 m/sec

★lift initial position = 40 m height

position after 3 minutes,

\longrightarrow1 minute = 60 secs

therefore, 3 minutes = 3 × 60 = 180 secs

Lift moves in 15 secs = 4 m

\longrightarrow Lift moves in 1 sec = \sf\frac{4}{15}\\ m

\longrightarrow Lift will move in 180 secs = 18 × \sf\frac{4}{15}\\

\longrightarrow Lift will move in 180 secs = 12 × 4 m

Position of lift after 3 minutes = 40 - 48 = (-8)m

\longrightarrow lift position will be at depth of 8m.

Lift position will be at the depth of 8m after 3 minutes.

Answered by Anonymous
78

\dag\:\:\underline{\sf Question:- :}

A multistorey building has parking floor at the basement. A lift moves at the rate of 4 m per 15 seconds. If the lift starts coming down from a height of 40 m, then find its position after 3 minutes.​

\dag\:\:\underline{\sf Answer:- :}

  • Given:-\left \{ {{Height = 40 m} \atop {Velocity = 4m/15 secs}} \right.

  • To find :-\left \ {{Position \: of \: the \: lift \: after \: 3 \: minutes}

Solution :-

We know that,

      1 minute = 60 secs

∴ 3 minutes = (60) (3)

                    = 180 secs

Distance covered by the lift in 15 sec = 4 m

Distance covered by the lift in 1 sec = \frac{4}{15} m

Distance covered by the lift in 180 secs = 18 × \frac{4}{15} m

                                                                  = (12)(4) m

                                                                  = 48 m

∴ Position of the lift after 3 minutes (180 secs) = 40 - 48

                                                                             = -8 m

∴ The lift will be at a depth of 8 m from the ground after 3 minutes.

Hope this helps! ♡

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