A multistory building has parking floor at the basement. A lift moves at the rate of 4m,per 15 seconds, if the lift starts coming down from a height of 40m, then find the position after 3 minutes.
Answers
Answer: A multistory building has parking floor at the basement. A lift moves at the rate of 4m,per 15 seconds,
To find : position of lift after 3 minutes.
Solution:
Lift speed = 4 m/ sec
lift initial position = 40 m height
Position after 3 minutes
1 minute = 60 secs
=> 3 minutes = 3 * 60 = 180 Secs
Lift moves in 15 Secs = 4 m
=> Lift moves in 1 Sec = 4/15 m
=> Lift will move in 180 secs = 180 * 4/15
=> Lift will move in 180 secs = 12 * 4 = 48 m
position of lift after 3 minutes = 40 - 48 = - 8m
=> lift position will be at depth of 8 m
lift position will be at depth of 8 m after 3 minutes
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The position after 3 minutes is 8100 meters.
Given:
Initial velocity = 0 m/s = u
Final velocity = 60 m/s = v
Time = 3 minutes = 180 seconds = t
Step-by-step explanation:
The equation of motion used is:
v = u + at
On substituting the values, we get,
4 = 0 + (a × 180 )
a = 4/180
∴ a = 1/45 m/s²
The equation of motion used is:
v² - u² = 2as
On substituting the values, we get,
360 - 0 = 2 × 1/45 × s
360 = 2/45 × s
s = 360 × 45/2 = 180 × 45
∴ s = 8100 m