A musician using an open flute of length 50 cm produces second harmonic sound waves. A person runs towards the musician from another end of a hall at a speed of 10 km/h. If the wave speed is 330 m/s, the frequency heard by the running person shall be close to
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Given length of the flute is l= 0.5 m
speed of the sound wave= 330 m/s
Frequency produced by the flute,
f= 2(V₀/2l) [as it produces 2nd harmonic]
=(2×330)/(2×0.5)=660 Hz
From Doppler's effect,
speed of the person V= 10×(5/18)=25/9 m/s
So frequency heard by the running person is
f₀=[(V+V₀)/V]f
=[{(5/9)+330}/330]×660=671.12 Hz
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