A myopia person uses specs of power _0.2d what is the distance of far point of his eye
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Answer:
500 cm
Explanation:
D=1/f
-0.2=1/f
f=-5m
f=-500cm
1/v-1/u=1/f
u=-infinite
1/v+1/infinite=-1/500
1/v=-1/500
v=-500cm
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