A myopic adult has a far point at 0.1 m. What power lenses are required to see distant objects?
[Take the image distance from the lens of the eye to the retina to be 2cm]
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Given:
The far point of the eye, u = -0.1 m
Image distance, v = 2 cm = 0.02 m
To Find:
The power of lenses required to correct the vision.
Calculation:
- Power of the eye lens:
P = 1/f = (1/v) - (1/u)
=> P = (1/0.02) - (1/-0.1)
=> P = 50 + 10 = 60 D
- When lenses are used, far point shifts to infinity.
=> u' = ∞
- Power with glasses:
P' = 1/f' = (1/v) - (1/u')
=> P' = (1/0.02) - (1/∞)
=> P' = 50 D
- Power of lenses = Power with glasses - Power of eye
=> P = 50 - 60
=> P = - 10 D
- So, the power of lenses required to correct the vision of the eye is -10 D.
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