Question

a(n)=−6+3(n−1)
Find the 16th term in the sequence.

Answer 1

Answer:

according to me this is the answer

Answer 2

$Given \: \blue{ n^{th} \: term \:a(n) = -6 + 3(n-1) }$

/* Substitute n = 16 in the above equation , we get */

$\red{ 16^{th} \:term \: a(16) \:in \: the \: sequence} \\= -6 + 3( 16 - 1 ) \\= -6 + 3 \times 15 \\= -6 + 45 \\= 39$

Therefore.,

$\red{ 16^{th} \:term \: a(16) \: in \: the \: sequence} \\\green { = 39 }$

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