Question

A
n
is
Truquale DOR
(PQR = 30° Find
isoscells
mLQSR and
with Pa a PR
m/QTR​

Answer 1

Answer: In △PQR, we have

PQ = PR

⇒ ∠PQR = ∠PRQ

⇒ ∠PRQ = 35˚

∴ ∠QPR = 180˚ - (∠PQR + ∠PRQ)

= 180˚ - (35˚ + 35˚) = 110˚.

Since, PQTR is a cyclic quadrilateral.

∴ ∠P + ∠T = 180˚

⇒ ∠T = 180˚ – 110˚ = 70˚

In cyclic quadrilateral QSRT, we have

∠S + ∠T = 180˚

⇒ ∠S = 180˚ - 70˚ = 110˚

Step-by-step explanation: