A n isosceles triangle abc with ab=ac a circile passing through b and
c. Intesect the sides ab and ac at d and
e. Prove that de is parallel to bc
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Answer:
DE || BC
Step-by-step explanation:
to prove :DE || BC
1 = 5 corresponding angles
proof : 1+4= 180 ... opp angles of cyclic quadrilateral
1 + (180-6) = 180
1+6=180
similarly
2+5=180
but ,
1=2.... isosceles ∆ theorem
therefore 1=5
DE || BC
{1,2,3,4,5,6 ARE THE ANGLES}
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