A nail entered into a wooden block upto 75mm when a hammer of 500 gram with a velocity of 15m/s , strike the nail. Taking the reaction force given by wooden block constant,calculate the following
1.the acceleration of the hammer
2.the value of the constant force.
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Answer:
mass of hammer is equal to ,m is 500 grams is 0.5 kg
initial velocity of hammer ,u is 50 m/s
time taken by the nail to stop the hammer,is 0.01
velocity of the hammer (since the hammer finally comes rest) fist newtons 2 and law of motion:
Explanation:
From Newton’s second law of motion:
Force, f = m(v-u) / t
= 0.5(0-50) / 0.01
= -2500 N
The hammer strikes the nail with a force of 2500 N. Hence, from Newton’s third law of motion, the force of the nail on the hammer is equal and opposite, i.e., +2500 N.
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