A nail has 2 cm at one end 1 cm and at the other end. A 100 force of 1000 g. wt is applied on the first end. Calculate the pressure acting on the wall?
Answers
Answered by
1
Answer:Thrust acting = force applied
F=1000gwt
The area of contact of the nail with the wall (A)=1/100cm
2
Pressure=
Area of contact
Thrust acting
∴P=
1/100
1,000
=(1000×100)
=10
5
gwtcm
−2
(∵1gwt=980dyne)
=980×10
5
dynecm
−2
Therefore, pressure acting on the wall is 98×10
6
dynecm
−2
.
Explanation:
Similar questions