Question

a nail has 2 cm square at one end 1/100cm² at the other end. a force of 1000g wt is applied on the first end. calculate the pressure acting on the wall​

Answer 1

Answer: 9.8 × 10^6 N/m²

Dear student,

Pressure acting on the wall will be due to

other end so,

Pressure= force/area

P= [1000×(1/1000) ×9.8] / [(1/100)×10^-4m2)]

P= 9.8×10^6 N/m²

Answer 2

The pressure acting on the wall  is $9.8\times10^{6}\ N/m^2$

Explanation:

Given that,

Area of one end = 2 cm  

Area of other end $A_{2}=\dfrac{1}{100}\ cm^2$  

Force on first end = 1000g  

Pressure :  

Pressure is directly proportional to the force and inversely proportional to the area.

We need to calculate the pressure acting on the wall

Using formula of pressure

Put the value into the formula

$P=\dfrac{1000\times9.8\times10^{-3}}{\dfrac{1}{100}\times10^{-4}}$

$P=9.8\times10^{6}\ N/m^2$

Hence, The pressure acting on the wall  is $9.8\times10^{6}\ N/m^2$

Learn more :

Topic : pressure

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