Question

A nail has 2cm square at one end and 100cm square at the other end . A force of 50N is applied on the first end. The pressure acting on the wall will be ?

Answer 1

Answer:

The pressure acting on the wall  is $9.8\times10^{6}\ N/m^2$

Explanation:

Given,

• Area of one end ($A_1$) = 2 cm  

• Area of other end ($A_2$) = $\dfrac{1}{100}\ cm^2$

• Force on first end = 1000 g  

Pressure is directly proportional to the force and inversely proportional to the area.

We need to calculate the pressure acting on the wall.

Using formula of pressure,put the value into the formula

$P=\dfrac{1000\times9.8\times10^{-3}}{\dfrac{1}{100}\times10^{-4}}$

$P=9.8\times10^{6}\ N/m^2$

Hence,

The pressure acting on the wall  is $9.8\times10^{6}\ N/m^2$

Answer 2

ANSWER:

The pressure acting on the wall = $25\times{10}^{4}$ N/m²

GIVEN:

• Area of tip = 2 cm²

• Area of other end = 100 cm²

• Force = 50 N

TO FIND:

• The pressure acting on the wall

CONVERSION:

• 1 cm² = ${10}^{ - 4}$ m²

• 2 cm² = 2 × ${10}^{ - 4}$ m²

• 100 cm² = 0.01 m²

FORMULA:

• PRESSURE = FORCE / AREA

EXPLANATION:

The pressure acting on the wall = 50 / 0.0002

The pressure acting on the wall = $25\times{10}^{4}$ N/m²

NOTE:

• Here area of the tip is taken because the tip exerts the force on the wall.

• The force what we give on the other end will be 50/0.01 = 5000N/m²

• This is quite less than the pressure exerted on the wall.

• This is because pressure is inversely proportional to the area. Hence less area facilitates more pressure on the wall.

SOME MORE POINTS:

• SI UNIT OF PRESSURE = N/m² or Pa

• DIMENSIONAL FORMULA = $[M {L}^{ - 1}{T}^{ - 2}]$

• UNITS AND DIMENSIONS OF STRESS, YOUNG'S MODULUS AND PRESSURE ARE THE SAME$\bigg(N/m^2\:\:or\:\:Pa\:\:and\:\:[M {L}^{ - 1}{T}^{ - 2}]\bigg)$