Question

a) name a green house gas with molar mass 44 g mole and is known to extinguish fire.b) Name the elements present in this gas and write their valency.c) Calculate the number of moles in 360 g of this gas sample.d) Calculate the number of molecules in 88 g of this gas sample. (Given atomic mass of C = 12 u, O = 16 u, $N_0$ = 6.022 × $10^{23}$ per mole)URGENT!!!

Answer 1

a. carbon dioxide b. carbon,oxygen c. No. of moles =360/44= 8.181 moles. d. No. of moles = 88/44= 2 no. of molecules= 2×6.022×10^23. =12.044×10^23 molecules

Answer 2

Answer:

Explanation: hope this helps

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