a narra tree costs a shadow of 28m long if its height is 40m how long is the shadow of another tree which is 60m at the particular time
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In △ABD,
tan60o=BDAB
3=xh
∴ x=3h ------- ( 1 )
Now in △ABC,
tan30o=BCAB
⇒ 31=x+40h
⇒ x+40=3h
∴ 3h+40=3h [ From equation ( 1 ) ]
⇒ h+403=3h
⇒ 2h=403
∴ h=203m
∴ The height of a tower is 20root3m.
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