Question

a narrow beam is incident On a 30degree-60 degree minus 90 degree prism perpendicular to the surface AB assumed that light beam is close to A.the index of reaction of prism is 2. see figure and take s
$\sin( \frac{10}{21} ) ^{ - 1} = 28 \: degree \: 26$
the beam emerges from the face

1) CB
2)AB
3)AC
4) some light through AC and remaining light through AB

PLEASE DONT SPAM,EXPLAIN IN DETAIL ​

Answer 1

Answer:

narrow beam is incident On a 30degree-60 degree minus 90 degree prism perpendicular to the surface AB assumed that light beam is close to A.the index of reaction of prism is 2. see figure and take s

$\sin( \frac{10}{21} ) ^{ - 1} = 28 \: degree \: 26$

the beam emerges from the face

3) AC

Answer 2

Explanation:

From the diagram, the angle at the bottom of the small top triangle is 30° so when we draw the normal line on that slanted interface, the angle of incidence there is 60°. We are told this is the critical angle which means the angle of refraction of the scenario is 90°. Now we use

ni sin θc = nr sin (90) … ni sin(60) = (1)(1) … ni = 1/ sin 60 …ni