Question

a narrow beam of light incident normally on the one face of an equilateral prism ( refractive index =1 .45) being surrounded by water (refractive index=1.44) . at what angle the ray of light emerges out?​

Answer 1

Explanation:

eμ

g

=

sinc

1

∠A=60

o

∠A+∠ARP=90

o

So, ∠ARP=30

o

So, ∠C=60

o

eμ

g

=

sin60

1

=

3

2

gμ

e

=

3/2

=0.866

aμ

e

=aμ

g

×gμ

e

=1.45×0.866=1.256