Question

A narrow glass tube, 80 cm long and opens at both ends, is half immersed in mercury, now the top of the tube is closed and is taken out of mercury. a column of mercury 20 cm long remains in the tube. find atmospheric pressure

Answer 1

Answer:

The atmospheric pressure will be equal to 60cm of mercury column.

Step-by-step explanation:

when we have half the tube is immersed in the mercury i.e 40 cm, the air pressure(P) inside the tube should be equal to the mercury pressure in the other half.

hence P =  ρgh = ρg40

Once the tube is removed with upper end closed, the air pressure inside will remain same. Now since the other end is open, this air pressure + the pressure of mercury remaining = the atmospheric pressure at the other end.

=> P₀ = P + ρgh₁

= ρgh + ρgh₁

= ρg(40 + 20)

= 60ρg

Hence atmospheric pressure will be equal to pressure of 60cm of mercury column.

Answer 2

Answer:

the answer is in the attachment

Step-by-step explanation:

thank you