a narrow glass tube 80 cm long and opens at both the ends is half immersed in mercury now the top of the tube is closed and is taken out of mercury . a 20cm long mercury column remains in the tube . find atmospheric pressure??
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When the glass tube was in mercury with half dipped Pressure on top of mecury should be equal to mercury pressure Therefore that pressure will be P(1) =13.6g(40)Now after taking tube out thumb is placed on the top so This should apply there also there now in this condition the pressure of mercury + P1= atmospheric pressure applying now on the other open end Therefore Atmospheric pressure=P1+13.6g(20) = 13.6g(40)+13.6g(20) =13.6g(60)Atmospheric pressure =60 cm of Hg column
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