Question

A narrow slit is illuminated by a parallel beam of monochromatic light of wavelength lambda equals to 6000 and strong and the angular width of the central maxima is resulting in diffraction pattern is measured when the slit is next illuminated by light of wavelength lambda dash the angular with decreases by 30% calculate the value of wavelength lambda dash

Answer 1

Explanation:

Angular width 2ϴ = 2λ/d Given λ = 6000 Å In Case of new λ (assumed λ’ here), angular width decreases by 30%  2 λ’/d = 0.70 X (2 λ/d) ∴ λ’= 4200 Å

if you find it helpful mark brainliest