Question

A narrow U-tube of uniform cross-section, having a liquid of density 'ρ', is made to move with an acceleration 'a' along the horizontal direction as shown in the figure. What should be the value of 'a' so that the difference in the level in the two arms of the tube is 3 cm (g = 10ms )​

Answer 1

Answer:

Explanation:

change in pressure in x direction similar to in Y direction

P A =0PB =fa 0L So,

Height of liquid in B=fgH=P  

B =fgH=fa  0 L H=  g a0 L