A national achievement test is administered annually to 3rd graders. The test has a mean score of 100 and a standard deviation of 15. If Jane's z-score is 1.20, what was her score on the test?
Answers
Answered by
2
Step-by-step explanation:
X= Z-SCORE * STANDARD DEVIATION + MEAN
=1.20(15)+100
=118
Answered by
12
Given:
mean score of 100 and a standard deviation of 15
- Jane's z-score is 1.20
- Let score on the test is x
- Here Z-score = 1.20
standard deviation = 15
Mean = 100
We have
x = Z-score × standard deviation + mean
x = 1.20 × 15 + 100
x = 18 + 100
x = 118
Hence the her score on the test is 118
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