a natural gas has a following composition by volume methane=82%, ethylene=12% N2=6% Calculate the density of gas at 288 k and 101.325kPa and composition in weight%
Answers
Answer:
This is a long question, so I will show only the calculations for methane. You can use them as a pattern for the ethane and nitrogen calculations.
The results are in the table below.
l
Item
m
m
CH
4
m
C
2
H
6
m
N
2
m
l
Total
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
Vol. %
m
m
l
83.6
m
l
l
12.5
m
m
l
4
m
m
l
100
Mole %
m
l
l
l
83.6
m
l
l
12.5
m
m
l
4
m
m
l
100
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
Moles
m
m
l
l
83.6
m
l
l
12.5
m
m
l
4
m
m
l
100
Mass/g
m
1341
m
m
375.8
m
110
m
m
1829
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
Mass %
m
l
l
l
73.3
m
l
l
20.6
m
m
l
6
m
m
l
100
Mole percent
Since
n
∝
V
, the volume percent is the same as the mole percent,
Mass percent
Assume that we have 100 mol of gas. Then we have
83.6 mol CH
4
,
12.5 mol C
2
H
6
, and
4 mol N
2
Mass of CH
4
=
83.6
mol CH
4
×
16.04 g CH
4
1
mol CH
4
=
1341 g CH
4
Calculate the masses of ethane and nitrogen in the same way.
Total mass = (1341 + 375.8 + 110) g = 1829 g
% CH
4
=
Mass of CH
4
Total mass
×
100
%
=
1341
g
1828
g
×
100
%
=
73.3
%
Calculate the mass percent of ethane and nitrogen in the same way.
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