Question

A natural no.is greater than 3 times it's square root by 4 .find the no.?
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Answer 1

Answer:

Answer:

let the no. be x

x>3×√x/4

4x/3>√x

16x^2/9>x

x>9/16

x=1.

Answer 2

Answer:

let the natural number is X

by the question,

x is greater than 3 times of sq root of X by 4

that is,

$x = 3 \sqrt{x} + 4 \\ > x - 4 = 3 \sqrt{x} \\ > {x }^{2} - 8x + 16 = 9x \: \: \: (squaring) \\ > {x }^{2} - 17x + 16 = 0 \\ > {x}^{2} - 16x - x + 16 = 0 \\ > x(x - 16) - 1(x - 16) = 0 \\ > (x - 16)(x - 1) = 0$

either,

x-16=0

>X=16

or,

x-1=0

>X=1

so X=16,1