Question

A natural number incresed by 84 eqal to 160 times of its resiprocal find number

Answer 1

Let the natural no be x
Then acc to ques
           x + 84 = 160 * 1/x
        x² + 84x = 160
⇒x² + 84x -160
Using quadratic formula
       x = -b+√b²-4ac/2a ,  -b-√b²-4ac/2a
       x = -84+√(84)²-4(1)(-160)/2(1)    , -84-√(84)²-4(1)(-160)/2(1)
       x = -84+√7056+640/2    ,  -84-√7056+640/2
       x = -84+87.72684879784524/2    ,  -84-87.72684879784524/2 
       x = 3.7268487978452/2     ,  -171.7268487978452/2
       x = 1.86342439892262          ,  -85.86342439892262

Negative neglected, so approximately the natural no would be 1.86

:) Hope this Helps !!!