A natural number incresed by 84 eqal to 160 times of its resiprocal find number
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Let the natural no be x
Then acc to ques
x + 84 = 160 * 1/x
x² + 84x = 160
⇒x² + 84x -160
Using quadratic formula
x = -b+√b²-4ac/2a , -b-√b²-4ac/2a
x = -84+√(84)²-4(1)(-160)/2(1) , -84-√(84)²-4(1)(-160)/2(1)
x = -84+√7056+640/2 , -84-√7056+640/2
x = -84+87.72684879784524/2 , -84-87.72684879784524/2
x = 3.7268487978452/2 , -171.7268487978452/2
x = 1.86342439892262 , -85.86342439892262
Negative neglected, so approximately the natural no would be 1.86
:) Hope this Helps !!!
Then acc to ques
x + 84 = 160 * 1/x
x² + 84x = 160
⇒x² + 84x -160
Using quadratic formula
x = -b+√b²-4ac/2a , -b-√b²-4ac/2a
x = -84+√(84)²-4(1)(-160)/2(1) , -84-√(84)²-4(1)(-160)/2(1)
x = -84+√7056+640/2 , -84-√7056+640/2
x = -84+87.72684879784524/2 , -84-87.72684879784524/2
x = 3.7268487978452/2 , -171.7268487978452/2
x = 1.86342439892262 , -85.86342439892262
Negative neglected, so approximately the natural no would be 1.86
:) Hope this Helps !!!
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