Question

a natural number is 3 more than the 2 times of square root of the same number find the natural number​

Answer 1

Answer:

9

Step-by-step explanation:

Let number be n

n=3+2√n

n-3=2√n

Squaring on both sides

(n-3)²=(2√n)²

n²-6n+9=4n

n²-10n+9=0

n²-n-9n+9=0

n(n-1)-9(n-1)=0

(n-1)(n-9)=0

n=1,9

But if we keep n=1 in above equation, it does not satisfy the condition

So, answer is 9