a natural number is choosen at random from the first 500.what is probability that the number so choosen is divisible by 3
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hey here is your answer and u can solve this question by A.P. also..
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a+(n-1)d
where a= first no. divisible by 3.
d=difference
n= no. of terms
so 3+(n-1)3=498
this gives..n=166
as per probability formula
166/500=83/250
where a= first no. divisible by 3.
d=difference
n= no. of terms
so 3+(n-1)3=498
this gives..n=166
as per probability formula
166/500=83/250
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