Question

A natural number is chosen at random from amongst the first 30. what is the probability
that number so chossen is
a) divisible by 4 and 5
b) a multiple of 4
c) an odd number
d) greater than 12​

Answer 1

Answer:

1. p(divisible by 4and 5)= 2/30= 1/15
2. p(multiple of 4)= 7/30 = 4.28
3. p(odd number) = 15/30= 1/2
4. p(greater then 12)= 18/30

Step-by-step explanation:

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