Question

A natural number is greater than that twice its square root by 3.find the number

Answer 1

Answer:

n-2√n=3

n-3= 2√n

(n-3)²= 4n

n²- 6n + 9 = 4n

n²-10n + 9= 0

n² - 9n- n +9= 0

(n-9) (n-1) = 0

n= 1,9

neglecting n=  1.

Hence the number is 9.

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