Question

A natural number is greater than the

other by 5. The sum of their squares is

73. Find the numbers.
​

Answer 1

$\huge\pink{\mathfrak{answer}}$

Let the second natural number be x.

∴ The first natural number is x + 5.

As per the given condition,

x2 + (x + 5)2 = 73

∴ x2 + x2 + 10x + 25 – 73 = 0

∴ 2x2 + 10x – 48 = 0

Dividing by 2, we get

x2 + 5x – 24 = 0

∴ x2 – 3x + 8x – 24 = 0

∴ x (x – 3) + 8 (x – 3) = 0

∴ (x – 3) (x + 8) = 0

∴x = 3 or x = - 8

∵ the natural number cannot be negative

∴ x = 3

and x + 5 = 3 + 5 = 8

∴ the first natural number is 8 and the second is 3.

$\huge\pink{\mathfrak{itzcandylove}}$

Answer 2

Answer:

the numbers are X= 3 and 3+5=8

Thank you

cross check : 9 + 64= 73