Question

A natural number is greater than three times its square roots by 4. Find the number

Answer 1

Please find the answer in the attachment below..

Answer 2

Answer:

16 is the number which is greater than three times its square roots by 4.

Step-by-step explanation:

Given that a natural number is greater than three times its square roots by 4. we have to find the number.

Let a natural number is x.

According to given statement equation becomes

$x=3\sqrtx+4$

⇒ $x-4=3\sqrtx$

Squaring on both sides , we get

$(x-4)^2=(3\sqrt x)^2\\\\x^2+16-8x=9x\\\\x^2-17x+16=0\\\\x^2-16x-x+16=0\\\\x(x-16)-1(x-16)=0\\\\(x-1)(x-16)=0\\\\x=1, x=16$

x=1 is not possible as it not satisfied the given statement.

Hence, 16 is the number which is greater than three times its square roots by 4.