Question

A natural number is greater than three times its square root by 4 find the number

Answer 1

Answer: 1 ( if we are taking square root of 1 as -1) or 16

Step-by-step explanation:

Let m be the required number

Then m=3sqrt(m)+4

3sqrt(m)=m-4

Squaring

9m=sq(m)-8m+16

sq(m)-17m+16=0

(m-1)(m-16)=0

m=1 or 16

[ 1=3sqrt(1)+4, here sqrt(1) is -1

16=3x4 + 4 ]

Answer 2

Answer:answer is 1 or 16 steps are above done by another user

Step-by-step explanation: