Question

a natural number is twice the other.if the difference of their cube is 5103. find the number​

Answer 1

Answer:

x=18 and y=9

Step-by-step explanation:

let the two natural no.s be= x and y

x=2y---------(1)

x^3-y^3=5103

now substituting (1)

(2y)^3-y^3=5103

8y^3-y^3=5103

7y^3=5103

y^3=729

y=9

therefore x=2y

                  =2 x 9

                  =18

HOPE THIS HELPS YOU......

PLS MARK AS BRAINLIEST.....

Answer 2

Answer:-

Let one of the numbers be a.

Given:

The second number is twice the first.

→ second number = 2(a) = 2a.

And,

Difference of their cubes is 5103.

→ (2a)³ - a³ = 5103

→ 8a³ - a³ = 5103

→ 7a³ = 5103

→ a³ = 5103/7

→ a³ = 729

→ a³ = 9³

Powers are equal , hence the bases are also equal.

→ a = 9

→ First number (a) = 9

→ second number (2a) = 9*2 = 18.

Verification:-

Given that, the difference of their cubes is 5103.

Hence,

(18)³ - (9)³ = 5103

→ 5832 - 729 = 5103

→ 5103 = 5103

→ LHS = RHS

Hence, Verified.