Question

A natural number lies between 9 and 100. What is the probability that the number chosen at random is a multiple of 11.

Answer 1

Answer:

9/92

Step-by-step explanation:

n= Total no.of ways(9to 100) = 92

m= Favourable no. of ways is the number of terms in the arithmetical series

11,22,33,44,55,66,77,88,99 .

∴92=4+(m−1)11 or m= 9

Hence required probability is = m/n = 9/92