English, asked by XxDREAMKINGxX, 1 month ago

a natural number when dived by 15 gives a remainder 13.what will be the same natural number divided by 5


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Answers

Answered by rohitsingh9014
2

Explanation:

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Answered by jiakher84
4

Answer:

Infinite such numbers exist.

The smallest positive integer would be 13. The next would be 28 (15+13).

To get more such numbers, take the multiple of 15 and add 13 to them. The list will include 13, 28, 43, 58, 73, 88, 103, 118, 133, 148, 163 and so on.

The numbers divided by 5 always give remainder 3

Or

N=15Q+13...where Q∈ N

N(1)=15×1+13=28

N(2)=15×2+13=43

Explanation:

The smallest number is 28, which when divided by 15 gives a remainder of 13 with a quotient of 1.

The next number is 28+15 or 43, which gives a remainder of 13 with a quotient of 2.

You can continue to add 15 each time to get a remainder of 13 and increasing number of quotients.

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