Math, asked by munnakrk, 5 hours ago

A natural number when divided by 12,15,18 leave remainder 5,8,11 respectively.Find sum of the digits of least such number?
A)9
B)10
C)11
D)12​

Answers

Answered by hukam0685
4

Step-by-step-Explanation:

Given: A natural number when divided by 12,15,18 leave remainder 5,8,11 respectively.

To find: Find sum of the digits of least such number?

A)9

B)10

C)11

D)12

Solution:

Step 1: Find LCM of 12, 15 and 18

Write prime factors of each number

12=2×2×3

15=3×5

18=2×3×3

LCM(12,15,18)= 2²×3²×5

LCM(12,15,18)= 4×9×5

LCM(12,15,18)= 180

Step 2: Find difference of each remainder from respective number

12-5=7

15-8=7

18-11=7

since, difference of each remainder is same.

Step 3: Subtract the difference of remainder from 180.

The natural number is 180-7=173

Step 4: Find sum of digits of 173

1+7+3=11

Option C is correct.

Final answer:

173 when divided by 12,15,18 leave remainder 5,8,11 respectively.

Sum of the digits of least such number is 11.

Option C is correct.

Hope it helps you.

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Answered by carboedits376
0

Answer:

Step-by-step explanation:

Solution:

Step 1: Find LCM of 12, 15 and 18

Write prime factors of each number

12=2×2×3

15=3×5

18=2×3×3

LCM(12,15,18)= 2²×3²×5

LCM(12,15,18)= 4×9×5

LCM(12,15,18)= 180

Step 2: Find difference of each remainder from respective number

12-5=7

15-8=7

18-11=7

since, difference of each remainder is same.

Step 3: Subtract the difference of remainder from 180.

The natural number is 180-7=173

Step 4: Find sum of digits of 173

1+7+3=11

Option C is correct.

Final answer:

173 when divided by 12,15,18 leave remainder 5,8,11 respectively.

Sum of the digits of least such number is 11.

Correct option is C

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