Question

 A natural number, when increased by 12, equals to 160 times of its reciprocal. Find the number.​

Answer 1

Let number be x

X + 12 = 160×1/x

X^2 + 12X - 160 =0

x^2 + 20x - 8x - 160=0

x (x+20)-8(x+20)=0

(x+20)(x-8)=0

x+20=0

x= -20

x-8=0

x= 8

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