Question

A natural number when increased by 84 equals 160 times it's reciprocals.Find the number​

Answer 1

Answer:

ANSWER

Let the natural number be x.

ATQ x+84=160(1/x)

x

2

+84x=160

x

2

+84x−160=0

Here a quadratic equation formed :

where a (coefficient of x

2

) =1

b (coefficient of x) =84

c (constant) =−160

D (discriminant) =b

2

−4ac

=84

2

−4(1)(−160)

=7696

∴ By quadratic formula.

−b±

D/2a

So 160−

7696/2

& 160+

7696/2