A natural number x is chosen at random from the first 100 natural numbers . find the probability that x+(100/x) > 50
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Answer:
ANSWER
Step-by-step explanation:
Given x+
x
100
>50⇒x
2
−50x+100>0
⇒(x−25)
2
>525⇒x−25<−
525
or x−25>
525
⇒x<25−
525
or x>25+
525
As x is a positive integer and
525
=22.91, we must have x≤2 or x≥48
Let E be the event for favorable cases and S be the sample space.
∴E={1,2,48,49,50,...100}
n(E)=55 and n(s)=100
Hence the required probability
P(E)=
n(s)
n(E)
=
100
55
=
20
11
by comparing it with
20
10+k
we get 10+k=11
∴k=1
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