Question

A naughty boy is standing at the edge of the roof of a multistoreyed building. He throws a ball making an angle a with vertical upward direction at t = 0. But he losses his balance after throwing the ball and starts to fall att = to. The ball reaches at ground at t = 10 to. But the boy reaches at ground safety at t = 5to. The path of ball observed by the boy is

Answer 1

Answer:

a=9.8\ m/s^2a=9.8 m/s2

Explanation:

We know that the acceleration of an object is given by :

a=\dfrac{dv}{dt}a=dtdv

i.e. acceleration is equal to the rate of change of velocity

We know that when a ball is projected vertically upwards, at the highest point the velocity of the ball is equal to zero. If the velocity is zero, its acceleration becomes constant.

So, at the highest point the acceleration at highest point is equal to 9.8 meters per second square. Hence, the correct option is (4).  

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Answer 2

Explanation: The answer is h/u= u^2÷20..

I hope it helps

Just take g=-10 because the force is acting in the opposite direction